![]() If the rest length is less than 4, the string is padded with '' characters. pad.length).forEach ĬhunkedSequence, require, and maybe String.repeat can be usefull. You can use the following regular expression to check if a string constitutes a valid base64 encoding: In base64 encoding, the character set is A-Z, a-z, 0-9, and + /. bytetoString doesn't do what you expect it to do it simply returns a representation of the byte array reference, not the contents of the byte array. The Java API contains a Base64 class, so you're probably best off using that. text.getBytes (encodingName)) Encode the bytes to base64 using the Base64 class. To encode your ciphertext use base 64 or hexadecimals. Transmitting end: Encode the string to bytes (e.g. It would be rare to use something other than UTF-8 or UTF-16. Android base64 decode not working Solved BASE64 Encode and Decode is not working 9to5Answer Guide to Base64 Encoding and Decoding Strings in Kotlin WebOct. Private val RX_BASE64_CLEANR = "".toRegex() UTF-8 is generally a good choice stick to an encoding which will definitely be valid on both sides. Clicking Encode will take input from top. Didn’t find base64 code that didn’t require importing java.this-or-that, so I tinkered a lil … private const val BASE64_SET = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/" Top multi line edit text for text, bottom multi line edit text for base 64. ![]()
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